LEETCODE
#7. Reverse Integer
로그앤
2023. 10. 10. 18:46
Given a signed 32-bit integer x, return x with its digits reversed. If reversing x causes the value to go outside the signed 32-bit integer range [-231, 231 - 1], then return 0.
Assume the environment does not allow you to store 64-bit integers (signed or unsigned).
Example 1:
Input: x = 123
Output: 321
Example 2:
Input: x = -123
Output: -321
Example 3:
Input: x = 120
Output: 21
class Solution:
def reverse(self, x: int) -> int:
result = 0
flag = 1
if x < 0:
flag = -1
else:
flag = 1
x = abs(x)
while x:
digit = int(x % 10 )
x = int(x // 10)
result = result * 10 + digit
return flag * result
# ans = str(abs(x))
# ans = ans.strip()
# ans = ans[::-1]
# if int(ans) > 2 **31 -1 or int(ans)< -2 ** 31:
# return 0
# if x > 0:
# return int(ans)
# else:
# return -1 * int(ans)