LEETCODE

#62. Unique Paths

로그앤 2023. 11. 1. 11:41
class Solution:
    def uniquePaths(self, m: int, n: int) -> int:
        dp = [[1] * n for _ in range(m)]

        for i in range(1, m):
            for j in range(1, n):
                # Calculate the number of unique paths for cell (i, j)
                dp[i][j] = dp[i-1][j] + dp[i][j-1]

        return dp[m-1][n-1]
        # if not m or not n:
        #     return 0
        # grid = [[0] * n for _ in range(m)]
        # grid[0][0] = 1
        # directions = [(1, 0), (0, 1)]
        # queue = deque([(0, 0)])

        # while queue:
        #     x, y = queue.popleft()
        #     for dx, dy in directions:
        #         new_x, new_y = x + dx, y + dy
        #         if 0 <= new_x < m and 0 <= new_y < n:
        #             grid[new_x][new_y] += grid[x][y]
        #             queue.append((new_x, new_y))

        # return grid[m - 1][n - 1]