Given an array nums of distinct integers, return all the possible permutations. You can return the answer in any order.
Example 1:
Input: nums = [1,2,3]
Output: [[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],[3,2,1]]
Example 2:
Input: nums = [0,1]
Output: [[0,1],[1,0]]
Example 3:
Input: nums = [1]
Output: [[1]]
class Solution:
def permute(self, nums: List[int]) -> List[List[int]]:
def DFS(visited, path):
if len(path) == n:
ANS.append(path[:])
return
for i in range(len(nums)):
if not visited[i]:
visited[i] = True
path.append(nums[i])
DFS(visited,path)
visited[i] = False
path.pop()
n = len(nums)
ANS = []
vis = [False] * len(nums)
DFS(vis,[])
return ANS
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